Question

0. A particle of mass m at rest is acted upon by a force P for time t. Its K.E after time t will be:

Answer 1

Answer:

 answer= P(square)t(square)/2m

Explanation:

 F=ma

v=u+at since here u=0

so, a=v/t

v=Pt/m

K.E.= 1/2m(v(square))

1/2*m*(Pt/m)(square)

answer= P(square)t(square)/2m