Question

Find the complement of the following Boolean function and reduce to a minimum number of literals.

B’D + A’BC’ + ACD + A’BC​

Answer 1

Answer:

B'D+A'BC'+A'BC+ACD

=B'D+A'B+ACD

So (B'D+A'B+ACD)'

=(B'D+A'B)'.(ACD)'

=((B'D)' . (A'B)'). (A'+(CD)')

=(B+D').(A+B').(A'+C'+D')

=(BA+D'A+D'B').(A'+C'+D')

=BAC'+BAD'+D'AC'+D'A+D'B'A'+D'B'C'+D'B'

=BAC'+BAD'+D'AC'+D'A+D'B'

=ABC'+AD'+D'B'

Explanation:

Answer 2

Answer:

thanku for helping

Explanation:

thanku , thanku very much