Chemistry, asked by janvihatwar, 7 months ago

°C С
(a) 22.4L (b)
9. Weight of CO2 in a 10 L cylinder at 5 atm and
27°C is
( 44 g (d) 89.3 g
g
20.​

Answers

Answered by shehzadi2325
2

Answer:

(d) 89.3g

Explanation:

PV = nRT

= m/M RT

P = 5atm V= 10L T= 300K

R = .0821 L atm K^-1 mol^-1

m = PVM/RT

= 5 x 10 x 44/ 0.0821 x 44

= 89.3g

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