Question

1.1. What is the force between two small charged spheres
having charges of 2 10-C and 3 x 10-'placed 30 cm
apart in air?​

Answer 1

Given:

Charge on the first sphere= $2*10 C$

Charge on the second sphere= $3*10C$

The distance between the charges= 30 cm

To find:

The force between the two small charged spheres.

Solution:

We know that the force of attraction by Columb's Law is given by:

$F=$$\frac{q_{1}q_{2} }{4\pi ∈ r^{2} }$      

Substitute the values of charge and separation between them and calculate the force.

$F=$$\frac{9*10^{-9} 2*10*3*10 }{ 30^{2}*10^{-4} }$    

$F=\frac{54*10^{-7} }{900*10^{-4} }$

$F=6*10^{-3}$

Thus, the force between two small charged spheres is $6*10^{-3}$ N