Math, asked by CapBlissSaigi3251, 10 months ago

பு‌ள்‌ளிக‌‌ள்(1,2) (3,-4) ம‌ற்று‌ம் (5,-6) இ‌ன் வ‌ழி‌ச் செ‌ல்லு‌ம் வ‌ட்ட‌த்‌தி‌ன் மைய‌ம்(11,2) எ‌ன ‌நிறுவுக

Answers

Answered by adityajoshi234519
0

Step-by-step explanation:

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Answered by steffiaspinno
0

விளக்கம்:

SA ன் தொலைவு

  \begin{array}{l}=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} \\=\sqrt{(11-1)^{2}+(2-2)^{2}}\end{array}

  \begin{aligned}&=\sqrt{10^{2}+0^{2}}\\&=\sqrt{10^{2}}\end{aligned}

SA ன் தொலைவு =10

SB  ன் தொலைவு

 \begin{aligned}&=\sqrt{(11-3)^{2}+(2+4)^{2}}\\&=\sqrt{8^{2}+6^{2}}\end{aligned}

  \begin{aligned}&=\sqrt{64-136}\\&=\sqrt{100}\end{aligned}

SB  ன் தொலைவு =10

SC ன் தொலைவு

\begin{aligned}&=\sqrt{(11-5)^{2}+(2+4)^{2}}\\&=\sqrt{6^{2}+8^{2}}\\&=\sqrt{36+64}\end{aligned}

=\sqrt{100}

SC ன் தொலைவு =10

S A=A B=S C

கொடுக்கப்பட்ட புள்ளிகள் வட்டத்தை அமைக்கும்.    

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