Question

1/3(3y-12)=6-2(y-1)
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Answer 1

Answer:

y = 0

Step-by-step explanation:

1/3 (3y - 12) = 6 - 2(y-1)

(opening the brackets)

(1/3 × 3y) - (1/3 × 12) = 6(y - 1) - 2(y-1)

y - 4 = 6y - 6 - 2y + 2

y - 4 = 4y - 4

4-4 = 4y - y

3y = 0

y = 0/3

y = 0

Hope it helps :))