Question

1) 4.88 g of KCIO3 when heated produced 1.92 g of oxygen and the residue (KCI) left behind weighs 2.96g. Show that these results illustrate the law of conservation of mass.

Answer 1

Answer:

2KClO

3→2KCl+3O2

Mass of the reactant = total mass of the products (2.96+1.92=4.88 g)

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. Therefore it is the law of conservation of mass