Question

1÷512,1÷128,1÷64 ..... is in G.P Then "r" value is

Answer 1

it doesn't forms GP. because 1/128/1/512 doesn't equals to. 1/64/1/128

Answer 2

The value of r is 4.

Step-by-step explanation:

Given : $\frac{1}{512},\frac{1}{128},\frac{1}{64},..$ is in G.P.

To find : The value of r ?

Solution :

In an G.P r is the common ratio i.e. $r=\frac{a_2}{a_1}$

Here, first term is $a_1=\frac{1}{512}$

Second term is $a_2=\frac{1}{128}$

The common ratio is

$r=\frac{\frac{1}{128}}{\frac{1}{512}}$

$r=\frac{512}{128}$

$r=4$

Therefore, the value of r is 4.

#Learn more

If 10th term of a g.p is 1536. and the first term of the g.p is 3.what is the 15th term of that g.p

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