Question

1. 54/mn(+ m)(m + n)(n + 1) + 81mn(m + n)(n + 1)
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Answer 1

Answer is 2 l (m+n) / 3 or (2 lm + 2 ln) / 3

Step-by-step explanation:

2 l (m+n) / 3

To solve, 54lmn (l + m) (m + n) (n + l) divided by 81mn (l + m) (n + l), we need to find the common factors between the numerator and denominator.

Here, we find that (l + m) and (n + l) are found in both the denominator and the numerator and hence can be cancelled.

So we get 54lmn (l + m) (m + n) (n + l) / 81mn (1 + m) (n + l) = 54lmn (m + n) / 81mn

Let's simplify this further by looking for more common factors. mn can be cancelled. Also 54 and 81 are both factors of 9

So we get 54lmn (m + n) / 81mn = 6 l (m + n) / 9 = 2 l (m + n) / 3

Answer is 2 l (m+n) / 3

Answer 2

Answer:

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