1.62×1.62-0.38×0.38 using identity
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Answered by
17
by using this identity a^2-b^2=(a+b)(a-b)
1.62^2-0.38^2=(1.62+0.38)(1.62-0.38)
=(2.00)( 1.14)
=2.28
1.62^2-0.38^2=(1.62+0.38)(1.62-0.38)
=(2.00)( 1.14)
=2.28
zoobi:
Thanks
Answered by
22
using identity a^2-b^2=(a+b)(a-b)
then 1.62^2-0.38^2
=(1.62+0.38)(1.62-0.38)
=2× 1.24
=2.48
then 1.62^2-0.38^2
=(1.62+0.38)(1.62-0.38)
=2× 1.24
=2.48
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