Question

(1) 6x - 3y = -10 ; 3x + 5y - 8 = 0 solve by simultaneouse equation ​

Answer 1

Answer:

(1) 6x - 3y = -10 ; 3x + 5y - 8 = 0 solve by simultaneouse equation

Answer 2

Step-by-step explanation:

Given:-

6x - 3y = -10 ; 3x + 5y - 8 = 0

To find:-

Solve the given equations ?

Solution:-

Given equations are:

6x - 3y = -10 -----------(1)

On multiplying with 3 both sides

18x - 9y = -30----------(2)

and

3x + 5y - 8 = 0

=> 3x + 5y = 8-----------(3)

On multiplying with 6 both sides then

=> 18x + 30y = 48 -------(4)

On subtracting (2) from (4)

18x + 30y = 48

18x - 9y = -30

(-)

____________

0 + 39 y = 78

____________

=> 39 y = 78

=> y = 78/39

=> y = 2

The value of y = 2 ---------(5)

On Substituting the value of y in (1) then

6x -3(2) = -10

=> 6x -6 = -10

=>6x = -10+6

=> 6x = -4

=> x = -4/6

=> x = -2/3

The value of x = -2/3

Answer:-

The solution for the given system of simultaneous equations is ( -2/3 , 2)

Check:-

If x = -2/3 and y = 2 then

LHS of equation (1)

=> 6(-2/3)-3(2)

=> -4-6

=> -10

=>RHS

LHS = RHS is true for (-2/3,2)

If x = -2/3 and y = 2 then

LHS of equation (3)

=> 3(-2/3)+5(2)

=> -2+10

=> 8

=> RHS

LHS = RHS is true for (-2/3,2)

Used Method:-

• Method of Elimination.