1+a^2+a^3+a Factorise this
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1+a²+a³+a
1 (1 + a²) +a (a²+ 1)
1 (1 + a²) + a (1 + a²)
(1 + a) (1 + a²)
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Step-by-step explanation:
a3+a2+a+1
=a3-a2+2a2-2a+a-1
= a2(a-1)+2a(a-1)+1(a-1)
=(a-1)(a2+2a+1)
=(a-1)[(a+1)whole square]
=(a-1)(a+1)(a+1)
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