1)A concave lens has a focal lenght of 15 cm.At what distance should the object be placed from the lens so that it forms an image at 10 cm from the lens?
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Answered by
6
focal length = -15cm
image distance = -10cm
object distance = ?
we will find object distance with a relation,
1/v - 1/u = 1/f
1/u = 1/v - 1/f
1/u = 1/-10 - 1/ -15
1/u = -1/10 + 1/15
1/u = -15 +10/150
1/u = -5/150
1/u = -1/30
u= -30
magnification,
m= v/u ( for lens)
m = -10/-30
m= 1/3
(or)
m= 0.33
thus the object must be placed 30cm from the mirror to get an image 10 cm.
hope it helps!!!!
image distance = -10cm
object distance = ?
we will find object distance with a relation,
1/v - 1/u = 1/f
1/u = 1/v - 1/f
1/u = 1/-10 - 1/ -15
1/u = -1/10 + 1/15
1/u = -15 +10/150
1/u = -5/150
1/u = -1/30
u= -30
magnification,
m= v/u ( for lens)
m = -10/-30
m= 1/3
(or)
m= 0.33
thus the object must be placed 30cm from the mirror to get an image 10 cm.
hope it helps!!!!
swathika23:
: )
Answered by
7
Focal length, f = -15 cm , since it is concave lens
Image distance, v = - 10 cm
Now image distance = u
By applying Lens formula,
1/v - 1/u = 1/f
- 1/10 - 1/u = -1/15
- 1/u = - 1/15 + 1/10
- 1/u = [- 2 + 3]/30
1/u = - 1/30
u = - 30 cm
So the object should be kept 30 cm in front of the lens
Hope This Helps You
Image distance, v = - 10 cm
Now image distance = u
By applying Lens formula,
1/v - 1/u = 1/f
- 1/10 - 1/u = -1/15
- 1/u = - 1/15 + 1/10
- 1/u = [- 2 + 3]/30
1/u = - 1/30
u = - 30 cm
So the object should be kept 30 cm in front of the lens
Hope This Helps You
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