1. A long wire carries a
Steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is B. It is then bent into a circular loop of 'n' turns. The magnetic field at
centre of the of coil will be?
a) nB
b) n²B
c) 2nB
d) 2n²B
Answers
Answered by
0
Answer:
Type your question...
12th
Physics
Moving Charges and Magnetism
Biot-Savart Law
A long wire carrying a stea...
PHYSICS
A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic filed at the centre of the loop is B. It is them bent into circular coil of n turns. The magnetic field at the centre of this cold of n turns will be.
October 15, 2019
avatar
Suneetha Khanwe
Share
Save
VIDEO EXPLANATION
ANSWER
The circumference of the first loop is the length of the wire=2πR
The magnetic field at the center of this wire=B=
2R
μ
0
I
The same wire is bent into n circular coils.
Thus new radius is found out by
n×2πr=2πR
⟹r=
n
R
Thus magnetic field at the center of these loops=n
2r
μ
0
I
=
2R
n
2
μ
0
I
=n
2
B
Similar questions