Question

1. A long wire carries a
Steady current. It is bent into a circle of one turn and the magnetic field at the centre of the coil is B. It is then bent into a circular loop of 'n' turns. The magnetic field at
centre of the of coil will be?
a) nB
b) n²B
c) 2nB
d) 2n²B​

Answer 1

Answer:

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12th

Physics

Moving Charges and Magnetism

Biot-Savart Law

A long wire carrying a stea...

PHYSICS

A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic filed at the centre of the loop is B. It is them bent into circular coil of n turns. The magnetic field at the centre of this cold of n turns will be.

October 15, 2019

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Suneetha Khanwe

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VIDEO EXPLANATION

ANSWER

The circumference of the first loop is the length of the wire=2πR

The magnetic field at the center of this wire=B=

2R

μ

0

I

The same wire is bent into n circular coils.

Thus new radius is found out by

n×2πr=2πR

⟹r=

n

R

Thus magnetic field at the center of these loops=n

2r

μ

0

I

=

2R

n

2

μ

0

I

=n

2

B