Question

1. A magnetic field of 2 x 10-3 T produces 'a flux of
2.4 x 10-5 Wb in an iron bar of cross-section 0.2 cm2,
calculate its permeability.


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Answer 1

Answer:

Magnetic Induction B=

Area

Flux

=

0.2×10

−4

2.4×10

−5

=1.2T

Permeability μ=

H

B

=

7.5×10

−4

1.2

=0.75×10

−3

Susceptibility X=624

u

0

u

=1+X

⟹

4π×10

−7

0.75×10

−3

=1+X⟹X=624

Explanation:

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