Question

1. A particle starts from rest, moves with constant acceleration for 15s. If it covers S1 distance in first 5s then
distance S2 in next 10s, then find the relation between S1 and S2.

with complete solution.​

Answer 1

v1=s1/5

v2=s2/10

$\frac{s1}{5} = \frac{s2}{10} \\ \frac{s1}{s2} = \frac{5}{10}$

s1:s2 =5:10

s1:s2=1:2

s2 is twice that of s1