Question

1.(a) The perimeter of a triangle is 7' - Sa. 11 and two of its sides are a +2a-1 and Ba'-6a. 3. Find the third side​

Answer 1

Answer:

Perimeter of △=7p

2

−5p+11

⇒p

2

+2p−1+3p

2

−6p+3+y=7p

2

−5p+11

⇒y=7p

2

−5p+11−4p

2

+4p−2=3p

2

−p+9

Third side =3p

2

−p+9

verified_toppr

Answer 2

Answer:

Perimeter of △=7p

2

−5p+11

⇒p

2

+2p−1+3p

2

−6p+3+y=7p

2

−5p+11

⇒y=7p

2

−5p+11−4p

2

+4p−2=3p

2

−p+9

Third side =3p

2

−p+9