Chemistry, asked by laibarashidawan1, 4 months ago

1.Calculate molarity of i. 40g of NaCl ii. 1 mole of Sulphuric acid *telll

Answers

Answered by sbdaule5

1

Answer:

i. 5/(7*V)

ii. 1/V

where V is volume in liters

Explanation:

molar weight of NaCl, M is 35+21=56

n = W/M = 40/56 = 5/7

molarity of solution depends on volume

so Molarity = n/Volume in liters

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