1) Calculate the resistance of a copper wire of length 1 m and area of cross section 2 mm2 . Resistivity of copper is 1.7 x 10 -8 Ω m .
pls can some1 solve it fast
Answers
Answered by
95
length of war is 1 m ( l ),
area of cross section is 2mm^2
=2×10^-6 m^2 ( a^2 )
resistivity of copper is 1.7×10^-8 ohm m( ¶ )
If resistance is R , we know
R=¶ × l / a^2
=1.7×10^-8 × 1 / 2×10^-6
=1.7 × 10^-8 ×10^6 /2
=1.7 × 10^-2 /2
=.0085 ohm
area of cross section is 2mm^2
=2×10^-6 m^2 ( a^2 )
resistivity of copper is 1.7×10^-8 ohm m( ¶ )
If resistance is R , we know
R=¶ × l / a^2
=1.7×10^-8 × 1 / 2×10^-6
=1.7 × 10^-8 ×10^6 /2
=1.7 × 10^-2 /2
=.0085 ohm
Answered by
0
Answer:
0.85x10*2
Explanation:
given:
resistivity:1.7x10*-8
length: 1 m
area: 2mm*2 = 2x10*-6
solution:
resistivity x length/area
1.7x10*-8 x 1 / 2x10*-6 [1.7/2=0.85]
0.85x10*2
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