1 cm of main scale of a vernier callipers is divided into 10 divisions. The least count of the callipers is 0.005 cm, then the vernier scale must have.
Answers
number of divisions of Vernier callipers would be 20.
given, 1 cm of main scale of a Vernier callipers is divided into 10 divisions.
so, width of each division = 1cm/10 = 0.1 cm
The least count of the callipers = 0.005 cm
we have to find the number of division of Vernier callipers.
least count = width of each division/number of divisions of Vernier callipers
⇒0.005 = 0.1/number of divisions of Vernier callipers
⇒number of divisions of vernier callipers = 0.1/0.005 = 1/0.05 = 20
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Total no of vernier scale division = 20
Given:
1 cm of main scale of a vernier calipers is divided into 10 divisions.
The least count of the calipers is 0.005 cm.
To find:
The vernier scale division.
Explanation:
1 main scale division= =
= 0.1 cm.
Least count = 0.005 cm. = 1 main scale division - 1 vernier scale division
1 vernier scale division = 0.1 - 0.005
= 0.095 cm.
Least count =
Total no of vernier scale division =
= 20
Total no of vernier scale division = 20
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1)When is A vernier calliper said to be free from the zero error ?
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(1)0.1 mm
(2)0.2 mm
(3)0.02 mm
(4)0.04 mm
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