Question

(1 - cos A) (1 +
+ sec A) = tan A sin A.​

Answer 1

$\huge\boxed{\fcolorbox{yellow}{orange}{☞✿ANSWER:-}}$

(1 - cos A) (1 + sec A)

(1 - cos A) (1 + 1 / cos A)

(1 - cos A ) ( 1 + cosA / cos A )

1 - cos²2A / cosA

As we know,

sin^2A + cos^2A = 1

So,

si^2A = 1 - cos^2A

Therefore,

sin^2A / cosA

( sinA / cosA ) × sinA

tanAsinA

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