1+cos2x+cos4x+cos6x=?
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1 + cos2x + cos4x + cos6x
=(1 + cos6x ) +(cos2x + cos4x)
= 2(cos3x)^2+ 2 cos 3xcosx
= 2cos3x[cos3x+cosx]
= 2cos3x(2cos2xcosx)
= 2cosxcos2xcos3x
=(1 + cos6x ) +(cos2x + cos4x)
= 2(cos3x)^2+ 2 cos 3xcosx
= 2cos3x[cos3x+cosx]
= 2cos3x(2cos2xcosx)
= 2cosxcos2xcos3x
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