Question

√1-cosa/√1+cosa=sina/1+cosa

Answer 1

hope this helps........ would love if you give brainliest.

Answer 2

Answer:

Step-by-step explanation:

The given equation is:

$\frac{\sqrt{1-cosa}}{\sqrt{1+cosa}}=\frac{sina}{1+cosa}$

Taking the LHS of the above equation, we get

$\sqrt{\frac{1-cosa}{1+cosa}}=\sqrt{\frac{(1-cosa)(1-cosa)}{(1+cosa)(1-cosa)}}$

=$\sqrt{\frac{(1-cosa)^{2}}{1-cos^{2}a}}= \sqrt{\frac{(1-cosa)^{2}}{sin^{2}a}}$

=$\frac{1-cosa}{sina}$

Multiplying an dividing by (1+cosa),we get

=$\frac{(1-cosa)(1+cosa)}{sin^{2}a(1+cosa)}$

=$\frac{1-cos^{2}a}{(1+cosa)sina}$

=$\frac{sina}{(1+cosa)}$

=RHS

Hence proved