Math, asked by prasanth1112, 10 months ago

1+cosecpi/4+cosecpi/8+cosecpi/16=​

Answers

Answered by rashmish107
1

Answer:

... (pi/8) ...... cos (pi/2^(n)) = [1/2^ (n-1)].cosec [pi/2^(n)]

Step-by-step explanation:

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