(1+cosx)(1-cosx)=3/4.find the value of secx
Answers
Answered by
0
hope that its correct
Attachments:
Answered by
0
(1+cosx)(1-cosx)=3/4 given value
1-cosx+cosx-cos^2x=3/4
1-cos^2x=3/4
1-3/4=cos^2x
(4-3)/4=cos^2x
1/4=cos^2x
1/cos^2x=4
sec^2x=4
secx=√4
secx=2
1-cosx+cosx-cos^2x=3/4
1-cos^2x=3/4
1-3/4=cos^2x
(4-3)/4=cos^2x
1/4=cos^2x
1/cos^2x=4
sec^2x=4
secx=√4
secx=2
Similar questions
Open code
-(cos(x) - 1) (cos(x) + 1) = 0.75 sec(x)
Open code
1/2 (1 - cos(2 x)) = 0.75 sec(x)
Open code
Expanded form:Step-by-step solution
1 - cos^2(x) = 0.75 sec(x)
Alternate form assuming x is real:
1 - cos^2(x) = (1.5 cos(x))/(cos(2 x) + 1) + 0. i
Open code
Enlarge Data Customize A Plaintext Interactive
Solutions:More rootsMore digitsExact formsStep-by-step solution
x≈2 (3.1416 n - (0.48989 + 0.25505 i) ), n element Z
plz mark me as a brainliest