1. Determine the nature of the roots of the equation.
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9x² + 12x + 4 = 0
where, a = 9 , b = 12 , c = 4
D = b² - 4ac
D = (12)² - 4(9)(4)
D = 144 - 144
D = 0
hence,the nature of the roots are real and equal.
where, a = 9 , b = 12 , c = 4
D = b² - 4ac
D = (12)² - 4(9)(4)
D = 144 - 144
D = 0
hence,the nature of the roots are real and equal.
Answered by
1
Compare given Quadratic equation
9x² + 12x + 4 = 0 with
ax² + bx + c = 0 we get
a = 9 , b = 12 , c = 4 ,
discreminant ( D ) = b² - 4ac
= ( 12 )² - 4 × 9 × 4
= 144 - 144
= 0
D = 0
Therefore,
Roots are real and equal.
••••
9x² + 12x + 4 = 0 with
ax² + bx + c = 0 we get
a = 9 , b = 12 , c = 4 ,
discreminant ( D ) = b² - 4ac
= ( 12 )² - 4 × 9 × 4
= 144 - 144
= 0
D = 0
Therefore,
Roots are real and equal.
••••
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