Question

1. Determine the nature of the roots of the equation.

Answer 1

3x² - 2√6x + 2 = 0
where, a = 3 , b = (-2√6) , c = 2

D = b² - 4ac

D = (-2√6)² - 4(3)(2)

D = 4*6 - 24

D = 24 - 24 = 0
hence,the nature of the roots are real and equal,

Answer 2

Compare given Quadratic equation

3x² - 2√6 x + 2 = 0 with

ax² + bx + c = 0 we get ,

a = 3 ,

b = -2√6 ,

c = 2 ,

Discreminant ( D ) = b² - 4ac

= ( -2√6 )² - 4 × 3 × 2

= 24 - 24

= 0

D = 0

Therefore ,

Roots are real and equal.

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