Question

1. Draw a triangle XYZ with sides XY = 4
cm, YZ = 5 cm and _Y = 60°. Then
5
construct a A whose sides are of the
3
corresponding sides of the first triangle.​

Answer 1

Step-by-step explanation:

im sorry it's bit messy but the correct solution

Answer 2

Answer:

The required triangle with scaler factor of 5/3 is Z'YX'

Step-by-step explanation:

Step 1: draw a line segment XY 4cm

Step 2: Mark 60° on Y by using protractor

Step 3: Take an arc of 5cm from Y and mark it from Y name it as Z

join all the points here XYZ triangle forms.

the length of sides of triangle are 5/3 times the sides of the given triangle

Draw an acute angle from Y take a compass and mark it from Y. Make other mark taking the same radius. We have to mark 5 marks because the greater no. between 5 and 3 is 5

YY1=Y1Y2=Y2Y3=Y3Y4=Y4Y5

Extend the line measure the angle at XY3Y then draw a line parallel to Y3X from Y5

Angle XYZ=60°

Draw a line parallel to XZ of an angle 60°

∠Y2Y3X = ∠Y4Y5X'

∠XYZ = ∠XX'Z'

So, Z'YX' is the new required triangle  with scaler factor of 5/3

#SPJ3