Question

1. Find group velocity of an
electron whose de Broglie
wavelength is 12 AU​

Answer 1

Answer:

Neutron m=1.67×10

−27

kg

l=

p

h

⇒P=

λ

h

=

1×10

−10

66×10

−34

kg m/s

⇒P=6.6×10

−24

kg m/s

energy E=

2m

P

2

=

2×1.67×10

−27

6.6×6.6×10

−48

joule

=

3.34

(6.6)

2

×10

−21

×

1.6×10

−19

1

ev

E = 0.8 ev