Question

1. find the equation of perpendicular bisectors of the line segment joining the points (1,1) and (2,3) 2. Find the eq of the line which passes through the points (3,4) and the sum of its intercepts on the axes 14

Answer 1

1. Given points :
A(1,1) , B(2,3)
The point that bisect the line AB
P = {(1+2)/2 , (1+3)/2}
P {(3/2),2}

The equation of line perpendicular to AB and passing through point P is ;
slope of AB =
m = 2
m'×2 = -1
m' = -1/2

equation of line
1x+ 2y +k =0
passes through point P
(3/2)+(2×2)+k = 0
(3/2) + 4 + k = 0
k = -11/2

the equation of the line is
x+2y-11/2 = 0
2x+4y-11 = 0