Question

1. Find the sum of all interior angles of the following regular polygons Nonagon Polygon of 11 sides Polygon of 16 sides​

Answer 1

Answer:

ok

Step-by-step explanation:

(i) Hexagon

Numbers of sides, n=6

Sum of the interior angles =(2n–4)900

=((2×6)–4)×900

=(12–4)900

=8×900

=7200

Sum of the exterior angles =3600.

 (ii) Octagon

Numbers of sides, n=8

Sum of the interior angles =(2n–4)900

=((2×8)–4)×900

=(16–4)900

=12×900

=10800

Sum of the exterior angles =3600.

(iii) Pentagon

Numbers of sides, n=5

Sum of the interior angles =(2n–4)900

=((2×5)–4)×900

=(10–4)900

=6×900

=5400

Sum of the exterior angles =3600.

 (iv) Nonagon

Numbers of sides, n=9

Sum of the interior angles =(2n–4)900

=((2×9)–4)×90

Answer 2

Answer:

1620° and 2520°.

Step-by-step explanation:

For Nonagon polygon of 11 sides

Using, (n-2)x180°

=(11-2)x180°

=9x180°

=1620°

For Polygon of 16 sides

Using, (n-2)x180°

=(16-2)x180°

=14x180°

=2520°