Question

1) find the value of k,if x-1 is a factor of p(x)
(i) p(x)=kx²-√2x+q
(ii) p(x)=kx²-3x+k​

Answer 1

Answer:

First one is (i) k=✓2+q

second one is (ii) k=3\2

Step-by-step explanation:

p(x)=x-1

x-1=0

x=1

(i) p(1)=kx²-✓2x+q

k(1)²-✓2(1)+q

k-✓2+q

-✓2+q= -k therefore - sign will be deducted

k=✓2+q

(ii) p(1)= kx²-3x+k

k(1)²-3(1)+k

k-3+k

2k-3=0

2k=3

k=3/2