Question

A bullet of mass 20 GMC is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg . What is the recoil velocity of the pistol

Answer 1

Answer:

mass1=0.02kg

u1=0m/s

v1=150m/s

mass2=2kg

u2=0m/s

v2=v.

∴by the law of conservation of momentum,

m1u1+m2u2=m1v1+m2v2

0.02*0+2*0=0.02*150+2*v

⇒0+0=3+2v

⇒3=2v

⇒3/2=v

⇒1.5=v

∴recoil velocity = 1.5 m/s

Answer 2

Answer:

1.5 m/s

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