Math, asked by ayushkr35, 10 months ago


1. Give reason to show that none of the numbers given below is a perfect square:
(i) 5372
(ii) 5963
(iii) 8457
(iv) 9468
(v) 360
(vi) 64000
(vii) 2500000​

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Answers

Answered by satyam2060
33

concept used:- a perfect square has only 1,4,9,6,5,0 at its unit digit and has even number of zeroes.

so here is the answer

1.

(i) 5372:- unit digit is 2 so it is not a perfect square.

(ii) 5963:- unit digit is 3 so it is not a perfect square

(iii) 8457:- Unit digit is 7 so it is not a perfect square.

(iv) 9468:- unit digit is 8 so it is not a perfect square

(v) 360 :- it has odd number of zeroes so it is not a perfect square

(vi) 64000:- it has odd number of zeroes so it is not a perfect square

(vii) 2500000:- it has odd number of zeroes so it is not a perfect square.

hope it helps you

please mark brainliest

Answered by 0xXIshuRajputXx0
3

Answer:

5372 .

Last no should no be = > 2 , 3 , 7 or 8 to be a perfect square .

It is not a perfect square .

5963 .

Last no should not be = 3

It is not a perfect square .

8457 .

Last no should no be 7 .

It is not a perfect square .

9468 .

Last no should not be 2 , 3 , 7 or 8 .

It is not a perfect square .

360 .

Last no should not be single zero .

It is not a perfect square .

64000 .

Last three no should not be three zero's .

It is not a perfect square .

2500000 .

Last five digits are zero which cannot make pair  , hence it is not a perfect square

Step-by-step explanation:

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