Math, asked by Avhir3254, 11 months ago

1.I am the first number divisible by both 6 and 9.Who am I???? 2.i am divisible by both 8 and 5.i lie between 195 and 205.Who am I??? 3.Find the smallest number divisible by 2,3,4,5,6and7???4.all whole numbers are my divisors. Who am I???? Plz answer with explanation friends... ​

Answers

Answered by marinette9
15

Answer:

1. 18

2. 200

3. I don't know

4. I guess 0

Step-by-step explanation:

1. because 18 is the first multipal which can multiple with 6 and 9..

2. 200 can divisible by both 5 ,8 and lies between 195 and 205.

3. I don't know sorry

Answered by arshikhan8123
0

Answer:

1. 18

2. 200

3. 420

4. 0 or 1

Explanation:

1)We are given a number divisible by both 6 and 9:

That is we need to calculate the LCM of 6 and 9:

LCM= 2×3×3

LCM= 18

So, the number is 18.

2)We are given that a number is divisible by both 8 and 5.

So, a number between 195 and 205 that is divisible by both 8 and 5 is 200.

3) We are given that a number is divisible by 2,3,4,5,6and7:

We will calculate the LCM.

LCM=2×3×2×5×7

LCM=420.

So, the number is 420.

4) We are given a number who is divisible by all the whole numbers.

The number will be 0 or 1.

Therefore, we have solved the different puzzles.

#SPJ3

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