1) If a student walks from his house to school at 5 kmph, he is late by 30 minutes. However, if he
walks at 6 kmph, he is late by 5 minutes only. The distance of his school from his house is :
Answers
Answer:
Hi there mate!!!
let me help you....
see, your question is simple, but you just need to understand it...
we are given two conditions with different speed and time, but the distance is common in both. therefore the answer of your question is as follows:-
1st situation:-
speed= 5km/h = 5 × 1000m / 60 min = 1km/12 min
time=30 min
According to the formula.....
speed = distance/ time
:. 1000m/12min = distance/ 30min
shift time to left hand side
100m/12min × 30min = distance
2nd situation....
speed= 6km/h = 6000m/60min = 100m/min
time= 5min
According to the formula....
speed = distance/ time
:. 100m/min = distance/5min
shift time to left hand side
100m × 5 = distance
now because the distance is same in both situations.....
:. 1000m/12 × 30 = 100m × 5
1000m/2 × 5 = 500m
500m × 5 = 500m
2500m = 500m
shift 500m to left hand side
2500m - 500m
2000m
:. 2km
therefore the distance from house to school is 2km.
Hope you liked the answer