Question

(1) If n(A)=15, n(AUB) = 29, nCANB) = 7 then nC)=
Solution :
MCAUB) - Du-mCANB)
29 = 15 + n(B) - 7
.. n(B) = 29-15+7
un(K) = 0​

Answer 1

Answer:

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

14=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

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