.1. If one of the zeros of the quadratic polynomial (k-1) x2 + kx+1y – 3, then the value of k is
a)4/3 b) -4/3 c)2/3 d) -2/3
i need with process
Answers
Answered by
4
My understanding of the question is:
Given (k-1)x² + kx + 1 has a (-3) as its zero.
So,
(k-1)(-3)² + k(-3) + 1 = 0
9k - 9 - 3k + 1 = 0
6k - 8 = 0
k = 8/6 = 4/3
Option A
Given (k-1)x² + kx + 1 has a (-3) as its zero.
So,
(k-1)(-3)² + k(-3) + 1 = 0
9k - 9 - 3k + 1 = 0
6k - 8 = 0
k = 8/6 = 4/3
Option A
Answered by
1
Step-by-step explanation:
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