1.if the lengths of the sides of a triangle are in the ratio 3:4:5 and its perimeter is 48cm find its area
2.the sides of a triangular plot are in the ratio 3:5:7 and its perimeter is 300 m. find iys area take square root of 3 =1.732
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Answered by
32
(1) Given that the sides of a triangle are 3x,4x,5x.
Given that perimeter of a triangle = 48cm.
3x + 4x + 5x = 48
12x = 48
x = 4.
Then the sides of a triangle are:
3x = 3 * 4 = 12
4x = 4 * 4 = 16
5x = 5 * 4 = 20
We know that semi-perimeter of a triangle s = a + b + c/2
= (12 + 16 + 20)/2
= 48/2
= 24.
We know that Area of a triangle =
=
=
=
= 96 cm^2.
(2) Given sides of the triangle are 3x,5x,7x
Given perimeter of a triangle = 300m.
3x + 5x + 7x = 300
15x = 300
x = 20.
Then the sides of the triangle are
3x = 3 * 20 = 60
5x = 5 * 20 = 100
7x = 7 * 20 = 140.
We know that semi-perimeter of a triangle s = (a + b + c)/2
= (60 + 100 + 140)/2
= 300/2
= 150m
We know that Area of a triangle =
=
=
=
=
=
=
=
=
=
= 1500 * 1.732
= 2598.
Hope this helps!
Given that perimeter of a triangle = 48cm.
3x + 4x + 5x = 48
12x = 48
x = 4.
Then the sides of a triangle are:
3x = 3 * 4 = 12
4x = 4 * 4 = 16
5x = 5 * 4 = 20
We know that semi-perimeter of a triangle s = a + b + c/2
= (12 + 16 + 20)/2
= 48/2
= 24.
We know that Area of a triangle =
=
=
=
= 96 cm^2.
(2) Given sides of the triangle are 3x,5x,7x
Given perimeter of a triangle = 300m.
3x + 5x + 7x = 300
15x = 300
x = 20.
Then the sides of the triangle are
3x = 3 * 20 = 60
5x = 5 * 20 = 100
7x = 7 * 20 = 140.
We know that semi-perimeter of a triangle s = (a + b + c)/2
= (60 + 100 + 140)/2
= 300/2
= 150m
We know that Area of a triangle =
=
=
=
=
=
=
=
=
=
= 1500 * 1.732
= 2598.
Hope this helps!
siddhartharao77:
Telangana. Hyderabad
Answered by
9
1) Given ratio of sides = 3 : 4 : 5
Let the sides be 3x , 4x , 5x .
Given perimeter = 48 cm
3x + 4x + 5x = 48
12 x = 48
x = 48/12 = 4 .
Therefore, the sides are 12 ,16 , 20 cm .
Semiperimeter = 48/2 = 24 CM.
Now Area of the triangle = √ 24(12)(8)(4)
= √12² * 2²*4²
= 12 * 2 * 4
= 96 cm².
2) Given ratio of sides = 3 : 5 : 7
Let the sides be 3x , 5x , 7x .
Given perimeter = 300 m
3x + 5x + 7x = 300m
15 x = 300 m
x = 300/15 = 20
Therefore, the sides are 60 ,100 , 140 m .
Semiperimeter = 300/2= 150 m.
Now Area of the triangular plot = √ 150(90)(50)(10)
= √3 * 50² * 3²* 10²
= 50*3*10√3
= 1500* 1.732m².
= 2598 m²
Let the sides be 3x , 4x , 5x .
Given perimeter = 48 cm
3x + 4x + 5x = 48
12 x = 48
x = 48/12 = 4 .
Therefore, the sides are 12 ,16 , 20 cm .
Semiperimeter = 48/2 = 24 CM.
Now Area of the triangle = √ 24(12)(8)(4)
= √12² * 2²*4²
= 12 * 2 * 4
= 96 cm².
2) Given ratio of sides = 3 : 5 : 7
Let the sides be 3x , 5x , 7x .
Given perimeter = 300 m
3x + 5x + 7x = 300m
15 x = 300 m
x = 300/15 = 20
Therefore, the sides are 60 ,100 , 140 m .
Semiperimeter = 300/2= 150 m.
Now Area of the triangular plot = √ 150(90)(50)(10)
= √3 * 50² * 3²* 10²
= 50*3*10√3
= 1500* 1.732m².
= 2598 m²
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