Question

1. If the sum of the first and tenth term of an arithmetic sequence is 24, then what is the sum of the fifth and sixth terms? (32, 42, 24, 25).​

Answer 1

Answer:

24

Step-by-step explanation:

$t_{1} + t_{10} = 24\\a + a + (10-1)d = 24\\2a + 9d = 24 \\\\\\t_{5} + t_{6} \\= a + 4d + a + 5d\\ = 2a +9d\\ = 24 (Above equation)$