Question

1.
In the figure shown, the two identical balls of mass Mand radius Reach, are placed in contact with each other on
the frictionless horizontal surface. The third ball of mass Mand radius R/2, is coming down vertically and has a
velocity = vo when it simultaneously hits the two balls and itself comes to rest. Then, each of the two bigger balls
will move after collision with a speed equal to
(1) 4v/15
(2) 2v/5
(3) v/ 5
(4) None​

Answer 1

Each of the two bigger balls  will move after collision with a speed equal to  v = vo/√5

Explanation:

According to law of conservation of momentum

Pi = pf

MVo = 2MVcosθ

MVo = 2MV √5/2

After cancellation

v = vo/√5

Thus each of the two bigger balls  will move after collision with a speed equal to  v = vo/√5

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the velocity of a ball thrown with a speed of 200 ms-1 at an angle 60 with the horizontal at it maximum height is?

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Answer 2

Answer:

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