Question

In the given figure BD = 30cm, AC = 20 cm find:
a. Angle x
b. Length of AD
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Answer 1

In triangle DCB,

tan30°=CD/BD

1/root3=CD/30

CD=30/root3

=10root3

In triangle ACD,

sin○=CD/AC

=10root3/20root3

=1/2

=sin30°

Therefore a).Angle x=30°

In triangle ADC,

tan30°=CD/AD

1/root3=10root3/AD

AD=10×root3×root3

=10×3

=30cm

Therefore,length of AD =30cm