1. In triangleABC, if AB=AC and angleA = 100, then
find angleB and angleC
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the triangle is isoceles so angles opposite to opposite sides are equal
a=b=40
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Answer:
∠B=∠C=40°
Step-by-step explanation:
Given: in triangle ABC, AB=AC
∠ACB=∠ABC (Angle opposite to equal sides are equal)
Let them be ''
Now in Triangle ABC, By Angle Sum Property
∠BAC +∠ACB+∠ABC=180°
100°++=180°
100° +2=180°
2=80°
=40°
∠ACB=40°
∠ABC=40°
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