Question

1. In which of the following situations, does the list of numbers involve make an
arithmetic progression, and why?
(i) The taxi fare after each km when the fare is Rs. 15 for the first km and Rs. 8 for
each additional km.

Answer 1

Answer:

the ans is yes

bcoz the eqaution would be

x = total fare

y = additional charge

so x = 15+8y

now if we put values of y we can see that we get the same differnce of 8 ( put y= 1 , 2 , 3 ) its is km travelled

so

ap is 15 , 23,31

Step-by-step explanation:

how does the equation came

8 is multiplied by x bcoz additional km charge is rs 8 so no. of km is y and amount is 8 so total distance is 8y

15 is added bcoz its charge for first km so it has to be added if he sits in taxi and goes anywhere

it is the compulsion charge to him so first term would also be 15 ❤

hope it helped you ❤

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Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

Hope this helps you ✌️