1 kg of water is boiled under a pressure of 2 atm at 120 degree centigrade if the volume occupied by water and steam on the given conditions are 10 to the power minus 3 m cube and 0.824 mm cube respectively find the work done and the increase in internal energy given latent heat equals to 2.2 into 10 to the power 6 joule per kg and 1 atm = to 1.013 into 10 to the power 5 newton per metre square
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