1 let the resistance of elecric ccomponent remain constant while the V across two ends of the component decreases to half it's former value. What change will occur in the current it?
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Answered by
1
Hello friend!!
Rajdeep here...
According to ohm's law, the current flowing through the circuit is directly proportional to the potential difference applied at its ends provided that physical quantities and temperature remain constant.
Thus, keeping the resistance unaltered, if you reduce the P.D. to half, the current will also reduce to half.
V = IR (by ohm's law)
Thus, V/2 = I/2 × R (if R is constant).
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Rajdeep here...
According to ohm's law, the current flowing through the circuit is directly proportional to the potential difference applied at its ends provided that physical quantities and temperature remain constant.
Thus, keeping the resistance unaltered, if you reduce the P.D. to half, the current will also reduce to half.
V = IR (by ohm's law)
Thus, V/2 = I/2 × R (if R is constant).
Thanks..
Please follow to get more answers!!
Answered by
0
♤ We know that
I = V/R
If V' = V/2
I' = V'/R
= V/2R
= 1/2
Therefore , the current will also become half of its previous value.
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