Question

. A body travels a distance of 15m from A to B and then moves a distance of 20m at right

angles to AB. Calculate the total distance travelled and the displacement.

Answer 1

Let the final point be C
Thetefore,
Total Distance=AB+BC
Distance=15m +20mDistance=35mDisplacement=Hypotenous of Triangle ABCDisplacement =(AC)^2=(AB)^2+(BC)^2=AC^2=15^2+20^2=AC^2=225+400=AC^2=625
Therefore,AC=√625
AC=25m

Answer 2

Hey !

AB = 15 M

20 m at right angle to AB = BC

BC = 20

Total distance = AB + BC
= 15 + 20
= 35 m
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Displacement is the shortest distance possible between initial and final position .

Initial position = A
Final position = C

Displacement = AC

AC² = AB² + BC²
= 15² + 20²
= 225 + 400
= 625

AC = √625
= 25

Displacement = AC = 25 m