1 mole equimolar mixture of Co and Co2 contains how many moles of oxygen atom
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Answer:
Molar mass of CO2 = 44g/mol
Number of moles of CO2 present in 88g of CO2 = 88g/44g mol-1
= 2 moles
1 mole of CO2 contains 2 moles of Oxygen atoms. Hence 2 moles of CO2 contains 4 moles of Oxygen atoms
1 mole of oxygen contains 6.023 X 1023 atoms of oxygen
4 moles of oxygen contains = 4 X 6.023 X 1023
= 24.092 X 1023
= 2.4092 X 1024 atoms of oxygen
Therefore 88g of CO2 Contains 2.4092 X 1024 atoms of oxygen
I hope you understand.
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