Question

1 mole of So2 occupies a volume of 350 ml at 300 k and 50 atm pressure . calculate the compressibility factor of the gas ?

Answer 1

solution :

given :-

pressure ( p) = 50 atm

volume (v ) = 350 ml

change in litre

1 ml = 0.001litre

350 ml = 0.350litre


n = 1 mole.

Temperature ( T) = 300 K

then

$z = \frac{PV}{nRT} \\ \\ z = \frac{50 \times 0.350}{1 \times 0.082 \times 300} \\ \\ = 0.711$

be brainly

Answer 2

Answer:

see the attachment

Explanation:

check out the attachment