Question

1. Mr. Gomez harvested 60 1/3 sacks of palay, 25 % sacks of corn and 18 % sacks of monggo. How many sacks of grains did he harvest in all?

A. What is asked?
B. What are given facts?
C. How will you solve the problem?
D. How is the solution done?
E. What is the answer?​

Answer 1

Answer:

(A)What is asked? ffffdcvyct

Answer 2

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Answer:

A. here, it is asked how many sacks of grains did he harvest in total.

B. the given facts are

• the number of sacks of palay
• the percentage of sacks that are corn
• the percentage of sacks that are monggo

C. to solve the problem, we first convert the given percentages into fractions. then, we convert the mixed fraction to an improper fraction. we will take the total number of sacks of grains as n. then, n = sum of all the fractions given.

D.

$60 \frac{1}{3} = \frac{181}{3} \\\frac{25}{100} = \frac{1}{4} \\\frac{18}{100} = \frac{9}{50}$

$n = \frac{181}{3} + \frac{1}{4} + \frac{9}{50}\\n = \frac{(181*100)+(1*75)+(9*6)}{300} \\n = \frac{18100 + 75 + 54}{300} \\n = \frac{18229}{300} \\n = 60 \frac{229}{300}$

E. almost 61 sacks (60  229/300)